def is_punct(self):
return len(self.word) == <NUM_LIT:1> and unicodedata.category(self.word)[<NUM_LIT:0>] == '<STR_LIT:P>'<EOL>
Whether the chunk is a punctuation mark.

        See also https://en.wikipedia.org/wiki/Unicode_character_property

        Returns:
          bool: True if it is a punctuation mark.