def parse_resource_path(path):
splits = path.split('<STR_LIT:/>')<EOL>return splits[<NUM_LIT:0>], splits[<NUM_LIT:1>:]<EOL>
Split the path to its elements.

    :param path: URL path
    :type path: str
    :return: name and rest of the path
    :rtype: tuple(str, list(str))