def next_monday_or_tuesday(dt):
dow = dt.weekday()<EOL>if dow == <NUM_LIT:5> or dow == <NUM_LIT:6>:<EOL><INDENT>return dt + timedelta(<NUM_LIT:2>)<EOL><DEDENT>elif dow == <NUM_LIT:0>:<EOL><INDENT>return dt + timedelta(<NUM_LIT:1>)<EOL><DEDENT>return dt<EOL>
For second holiday of two adjacent ones!
If holiday falls on Saturday, use following Monday instead;
if holiday falls on Sunday or Monday, use following Tuesday instead
(because Monday is already taken by adjacent holiday on the day before)