def nonzero(self):
msg = ("<STR_LIT>"<EOL>"<STR_LIT>"<EOL>"<STR_LIT>")<EOL>warnings.warn(msg, FutureWarning, stacklevel=<NUM_LIT:2>)<EOL>return self._values.nonzero()<EOL>
Return the *integer* indices of the elements that are non-zero.

.. deprecated:: 0.24.0
   Please use .to_numpy().nonzero() as a replacement.

This method is equivalent to calling `numpy.nonzero` on the
series data. For compatibility with NumPy, the return value is
the same (a tuple with an array of indices for each dimension),
but it will always be a one-item tuple because series only have
one dimension.

See Also
--------
numpy.nonzero

Examples
--------
>>> s = pd.Series([0, 3, 0, 4])
>>> s.nonzero()
(array([1, 3]),)
>>> s.iloc[s.nonzero()[0]]
1    3
3    4
dtype: int64

>>> s = pd.Series([0, 3, 0, 4], index=['a', 'b', 'c', 'd'])
# same return although index of s is different
>>> s.nonzero()
(array([1, 3]),)
>>> s.iloc[s.nonzero()[0]]
b    3
d    4
dtype: int64