def error(message, code=<NUM_LIT:1>):
if message:<EOL><INDENT>print('<STR_LIT>'.format(message), file=sys.stderr)<EOL><DEDENT>else:<EOL><INDENT>print(file=sys.stderr)<EOL><DEDENT>sys.exit(code)<EOL>
Print error message to stderr and exits with a status of 1 by default.