def _rm_is_reverse_comp_match(parts):
assert((parts[<NUM_LIT:8>] == "<STR_LIT:C>" and len(parts) == <NUM_LIT:15>) or (len(parts) == <NUM_LIT>))<EOL>return len(parts) == <NUM_LIT:15><EOL>
determine whether a repeat occurrence is a match to the reverse complement
of the concensus. Headers look like this::

  239 29.42 1.92 0.97 chr1 11 17 (41) C XX#YY (74) 104 1 m_b1s502i1 4

If the match is to the reverse complement, then there is a "C" at position
8 (zero-based index) and a total of 15 fields; otherwise the "C" is missing
and there are only 14 fields.

:param parts: the header line, as a tokenized list.