def nrow(records):
return len(records)<EOL>
Return the number of rows in the records

    :param records: a list of dictionaries
    :returns: an integer

    >>> movies = [
    ... {'title': 'The Holy Grail', 'year': 1975, 'budget': 4E5, 'total_gross': 5E6},
    ... {'title': 'Life of Brian', 'year': 1979, 'budget': 4E6, 'total_gross': 20E6},
    ... {'title': 'The Meaning of Life', 'year': 1983, 'budget': 9E6, 'total_gross': 14.9E6}
    ... ]
    >>> nrow(movies)
    3