def get_image_registry_url(self, image_name):
c = self._oc_command(["<STR_LIT>", "<STR_LIT>", image_name,<EOL>"<STR_LIT>"])<EOL>try:<EOL><INDENT>internal_registry_name = run_cmd(c, return_output=True)<EOL><DEDENT>except subprocess.CalledProcessError as ex:<EOL><INDENT>raise ConuException("<STR_LIT>" % ex)<EOL><DEDENT>logger.info("<STR_LIT>", internal_registry_name)<EOL>return internal_registry_name.replace("<STR_LIT:'>", "<STR_LIT>").replace('<STR_LIT:">', '<STR_LIT>')<EOL>
Helper function for obtain registry url of image from it's name
:param image_name: str, short name of an image, example:
    - conu:0.5.0
:return: str, image registry url, example:
    - 172.30.1.1:5000/myproject/conu:0.5.0