UpperCamelCase  							=						[0, 2, 4, 6, 8]
UpperCamelCase  							=						[1, 3, 5, 7, 9]

def 			lowercase_				(			_lowerCamelCase							:       int		,	_lowerCamelCase							:       int		,	_lowerCamelCase							:       list[int]		,	_lowerCamelCase							:       int):
    if remaining_length == 0:
        if digits[0] == 0 or digits[-1] == 0:
            return 0

        for i in range(length // 2 - 1		,	-1		,	-1):
            remainder += digits[i] + digits[length - i - 1]

            if remainder % 2 == 0:
                return 0

            remainder //= 10

        return 1

    if remaining_length == 1:
        if remainder % 2 == 0:
            return 0

        lowercase__ :   str    					=				0
        for digit in range(10):
            lowercase__ :   str    					=				digit
            result += reversible_numbers(
                0		,	(remainder + 2 * digit) // 10		,	_lowerCamelCase		,	_lowerCamelCase)
        return result

    lowercase__ :   Dict    					=				0
    for digita in range(10):
        lowercase__ :   int    					=				digita

        if (remainder + digita) % 2 == 0:
            lowercase__ :   Optional[Any]    					=				ODD_DIGITS
        else:
            lowercase__ :   str    					=				EVEN_DIGITS

        for digita in other_parity_digits:
            lowercase__ :   List[str]    					=				digita
            result += reversible_numbers(
                remaining_length - 2		,	(remainder + digita + digita) // 10		,	_lowerCamelCase		,	_lowerCamelCase		,	)
    return result

def 			lowercase_				(			_lowerCamelCase							:       int = 9):
    lowercase__ :   Tuple    					=				0
    for length in range(1		,	max_power + 1):
        result += reversible_numbers(_lowerCamelCase		,	0		,	[0] * length		,	_lowerCamelCase)
    return result


if __name__ == "__main__":
      print(f"{solution() = }")







"""simple docstring"""







from itertools import permutations


def      lowercase			(				A_       )->      bool:
  '''simple docstring'''







  if num[3] % 2 != 0:
    return False

  if (num[2] + num[3] + num[4]) % 3 != 0:
    return False

  if num[5] % 5 != 0:
    return False

  a						:		Optional[int]      							=			[7, 11, 13, 17]
  for i, test in enumerate(A_       ):
    if (num[i + 4] * 100 + num[i + 5] * 10 + num[i + 6]) % test != 0:
      return False
  return True


def      lowercase			(				A_ = 10       )->      int:
  '''simple docstring'''







  return sum(
      int("".join(map(A_  ,   A_       )       )       )
      for num in permutations(range(A_       )       )
      if is_substring_divisible(A_       )       )


if __name__ == "__main__":
 print(f'''{solution() = }''')






