
'''simple docstring'''





def   A			(							A_				:       list[list[int]]     ,				A_				:       list[list[int]]							):
						snake_case							:  List[Any]			=     []
						snake_case							:  Optional[Any]			=     len(A_							)
						for i in range(A_							):
												snake_case							:  Optional[Any]			=     []
												for j in range(A_							):
																		snake_case							:  Optional[Any]			=     0
																		for k in range(A_							):
																								snake_case							:  str			=     val + matrix_a[i][k] * matrix_b[k][j]
																		list_a.append(A_							)
												matrix_c.append(A_							)
						return matrix_c

def   A			(							A_				:       int							):
						return [[int(row == column							) for column in range(A_							)] for row in range(A_							)]

def   A			(							A_				:       int							):
						if n <= 1:
												return n
						snake_case							:  Optional[Any]			=     identity(2							)
						snake_case							:  str			=     [[1, 1], [1, 0]]
						snake_case							:  Optional[Any]			=     n - 1
						while n > 0:
												if n % 2 == 1:
																		snake_case							:  Tuple			=     multiply(A_     ,				A_							)
												snake_case							:  Dict			=     multiply(A_     ,				A_							)
												snake_case							:  Tuple			=     int(n / 2							)
						return res_matrix[0][0]

def   A			(							A_				:       int							):
						if n <= 1:
												return n
						snake_case							:  Optional[int]			=     0
						snake_case							:  Any			=     1
						for _ in range(2     ,				n + 1							):
												snake_case,       snake_case							:  Union[str, Any]			=     fiba, fiba + fiba
						return fiba

def   A			(							):
						for ordinal in "0th 1st 2nd 3rd 10th 100th 1000th".split():
												snake_case							:  List[str]			=     int(''''''.join(c for c in ordinal if c in '''0123456789'''							)							)  # 1000th --> 1000
												print(
												    F"""{ordinal} fibonacci number using matrix exponentiation is """
												    F"""{nth_fibonacci_matrix(A_							)} and using bruteforce is """
												    F"""{nth_fibonacci_bruteforce(A_							)}\n"""							)
						# from timeit import timeit
						# print(timeit("nth_fibonacci_matrix(1000000)",
						#              "from main import nth_fibonacci_matrix", number=5))
						# print(timeit("nth_fibonacci_bruteforce(1000000)",
						#              "from main import nth_fibonacci_bruteforce", number=5))
						# 2.3342058970001744
						# 57.256506615000035


if __name__ == "__main__":
						import doctest

						doctest.testmod()
						main()





"""simple docstring"""







def _A		(		lowercase						):







    """simple docstring"""
    a											=[]
    a											=1

    for i in range(len(lowercase						)						):
        if i + 1 < len(lowercase						) and text[i] == text[i + 1]:
            count += 1
        else:
            encoded.append((text[i], count)						)
            a											=1

    return encoded
def _A		(		lowercase						):







    """simple docstring"""
    return "".join(char * length for char, length in encoded						)


if __name__ == "__main__":
       from doctest import testmod

       testmod(name="""run_length_encode""", verbose=True)
       testmod(name="""run_length_decode""", verbose=True)