


"""simple docstring"""






import itertools
from pathlib import Path
def    A_ ( _lowerCAmelCase  :       list[str]							):






     """simple docstring"""

     _a     						=					[tuple(_lowerCAmelCase							) for login in logins]

     _a     						=					{char for login in split_logins for char in login}

     for permutation in itertools.permutations(_lowerCAmelCase							):
          _a     						=					True
          for login in logins:
               if not (
                   permutation.index(login[0]							)
                   < permutation.index(login[1]							)
                   < permutation.index(login[2]							)
               ):
                    _a     						=					False
                    break

          if satisfied:
               return int(''''''.join(_lowerCAmelCase							)							)

     raise Exception('''Unable to find the secret passcode'''							)
def    A_ ( _lowerCAmelCase  :       str = "keylog.txt"							):






     """simple docstring"""

     _a     						=					Path(_lowerCAmelCase							).parent.joinpath(_lowerCAmelCase							).read_text().splitlines()

     return find_secret_passcode(_lowerCAmelCase							)


if __name__ == "__main__":
   print(f'{solution() = }')



"""simple docstring"""






def    A_ ( _lowerCAmelCase  :       str,  _lowerCAmelCase  :       str							):






     """simple docstring"""

     if len(_lowerCAmelCase							) < len(_lowerCAmelCase							):
          return levenshtein_distance(_lowerCAmelCase,  _lowerCAmelCase							)

     if len(_lowerCAmelCase							) == 0:
          return len(_lowerCAmelCase							)

     _a     						=					list(range(len(_lowerCAmelCase							) + 1							)							)

     for i, ca in enumerate(_lowerCAmelCase							):
          _a     						=					[i + 1]

          for j, ca in enumerate(_lowerCAmelCase							):
               # Calculate insertions, deletions and substitutions
               _a     						=					previous_row[j + 1] + 1
               _a     						=					current_row[j] + 1
               _a     						=					previous_row[j] + (ca != ca)

               # Get the minimum to append to the current row
               current_row.append(min(_lowerCAmelCase,  _lowerCAmelCase,  _lowerCAmelCase							)							)

          # Store the previous row
          _a     						=					current_row

     # Returns the last element (distance)
     return previous_row[-1]


if __name__ == "__main__":
   __snake_case												=							input('''Enter the first word:\n''').strip()
   __snake_case												=							input('''Enter the second word:\n''').strip()

   __snake_case												=							levenshtein_distance(first_word, second_word)
   print(f'Levenshtein distance between {first_word} and {second_word} is {result}')