


def 		_UpperCAmelCase							(     SCREAMING_SNAKE_CASE__     :   Union[str, Any]     ,	SCREAMING_SNAKE_CASE__     :   int							):
     if n < 0:
          return 0
     # table[i] represents the number of ways to get to amount i
     __UpperCamelCase       				=[0] * (n + 1)

     # There is exactly 1 way to get to zero(You pick no coins).
     __UpperCamelCase       				=1

     # Pick all coins one by one and update table[] values
     # after the index greater than or equal to the value of the
     # picked coin
     for coin_val in s:
          for j in range(SCREAMING_SNAKE_CASE__     ,	n + 1							):
               table[j] += table[j - coin_val]

     return table[n]


if __name__ == "__main__":
   import doctest

   doctest.testmod()









import math

def 		_UpperCAmelCase							(     SCREAMING_SNAKE_CASE__     :   int							):
     __UpperCamelCase       				=math.log(2     ,	10							) * number
     __UpperCamelCase       				=round((log_number - int(SCREAMING_SNAKE_CASE__							))     ,	15							)

     return difference

def 		_UpperCAmelCase							(     SCREAMING_SNAKE_CASE__     :   int = 67_89_10							):
     __UpperCamelCase       				=90
     __UpperCamelCase       				=0

     __UpperCamelCase       				=math.log(1.23     ,	10							)
     __UpperCamelCase       				=math.log(1.24     ,	10							)
     __UpperCamelCase       				=0

     while position < number:
          __UpperCamelCase       				=log_difference(SCREAMING_SNAKE_CASE__							)

          if difference >= upper_limit:
               power_iterator += 93

          elif difference < lower_limit:
               power_iterator += 1_96

          else:
               __UpperCamelCase       				=power_iterator
               power_iterator += 1_96
               position += 1

     return previous_power


if __name__ == "__main__":
   import doctest

   doctest.testmod()

   print(f"""{solution() = }""")





