"""simple docstring"""







import itertools
from pathlib import Path



def       A__    (	lowercase_     :	list[str]						)  ->							int:
   __lowerCamelCase    		=					[tuple(lowercase_						) for login in logins]

   __lowerCamelCase    		=					{char for login in split_logins for char in login}

   for permutation in itertools.permutations(lowercase_						):
      __lowerCamelCase    		=					True
      for login in logins:
         if not (
             permutation.index(login[0]						)
             < permutation.index(login[1]						)
             < permutation.index(login[2]						)
         ):
            __lowerCamelCase    		=					False
            break

      if satisfied:
         return int(''.join(lowercase_						)						)

   raise Exception('Unable to find the secret passcode'						)



def       A__    (	lowercase_     :	str = "keylog.txt"						)  ->							int:
   __lowerCamelCase    		=					Path(lowercase_						).parent.joinpath(lowercase_						).read_text().splitlines()

   return find_secret_passcode(lowercase_						)


if __name__ == "__main__":
     print(F"{solution() = }")













"""simple docstring"""





def    a__       (       _SCREAMING_SNAKE_CASE	,						_SCREAMING_SNAKE_CASE     ):




		"""simple docstring"""


		UpperCamelCase =						sorted(_SCREAMING_SNAKE_CASE	,						key=lambda _SCREAMING_SNAKE_CASE     : value[2]	,						reverse=_SCREAMING_SNAKE_CASE     )

		# Create a list of size equal to the maximum deadline
		# and initialize it with -1
		UpperCamelCase =						max(_SCREAMING_SNAKE_CASE	,						key=lambda _SCREAMING_SNAKE_CASE     : value[1]     )[1]
		UpperCamelCase =						[-1] * max_deadline

		# Finding the maximum profit and the count of jobs
		UpperCamelCase =						0
		UpperCamelCase =						0
		for job in jobs:
				# Find a free time slot for this job
				# (Note that we start from the last possible slot)
				for i in range(job[1] - 1	,						-1	,						-1     ):
						if time_slots[i] == -1:
								UpperCamelCase =						job[0]
								count += 1
								max_profit += job[2]
								break
		return [count, max_profit]


if __name__ == "__main__":
						import doctest

						doctest.testmod()






