

from __future__ import annotations

# Define the Gravitational Constant G and the function
lowercase_									=    6.6_7_4_3e-1_1  # unit of G : m^3 * kg^-1 * s^-2
def 		_snake_case(       SCREAMING_SNAKE_CASE__     :      float       ,     SCREAMING_SNAKE_CASE__     :      float       ,     SCREAMING_SNAKE_CASE__     :      float       ,     SCREAMING_SNAKE_CASE__     :      float )				-> dict[str, float]:





    '''simple docstring'''






    A__        =  mass_a * mass_a

    if (force, mass_a, mass_a, distance).count(0 ) != 1:
        raise ValueError('One and only one argument must be 0' )
    if force < 0:
        raise ValueError('Gravitational force can not be negative' )
    if distance < 0:
        raise ValueError('Distance can not be negative' )
    if mass_a < 0 or mass_a < 0:
        raise ValueError('Mass can not be negative' )
    if force == 0:
        A__        =  GRAVITATIONAL_CONSTANT * product_of_mass / (distance**2)
        return {"force": force}
    elif mass_a == 0:
        A__        =  (force) * (distance**2) / (GRAVITATIONAL_CONSTANT * mass_a)
        return {"mass_1": mass_a}
    elif mass_a == 0:
        A__        =  (force) * (distance**2) / (GRAVITATIONAL_CONSTANT * mass_a)
        return {"mass_2": mass_a}
    elif distance == 0:
        A__        =  (GRAVITATIONAL_CONSTANT * product_of_mass / (force)) ** 0.5
        return {"distance": distance}
    raise ValueError('One and only one argument must be 0' )


# Run doctest
if __name__ == "__main__":
     import doctest

     doctest.testmod()






'''simple docstring'''



def 							__UpperCAmelCase				(				UpperCamelCase__				:int   ,				UpperCamelCase__				:list			)		->						list:
				snake_case__      :   List[str]      =    sorted(UpperCamelCase__   ,				key=lambda UpperCamelCase__			: value[2]   ,				reverse=UpperCamelCase__			)

				# Create a list of size equal to the maximum deadline
				# and initialize it with -1
				snake_case__      :   Any      =    max(UpperCamelCase__   ,				key=lambda UpperCamelCase__			: value[1]			)[1]
				snake_case__      :   str      =    [-1] * max_deadline

				# Finding the maximum profit and the count of jobs
				snake_case__      :   List[str]      =    0
				snake_case__      :   Optional[Any]      =    0
				for job in jobs:
								# Find a free time slot for this job
								# (Note that we start from the last possible slot)
								for i in range(job[1] - 1   ,				-1   ,				-1			):
												if time_slots[i] == -1:
																snake_case__      :   Optional[Any]      =    job[0]
																count += 1
																max_profit += job[2]
																break
				return [count, max_profit]


if __name__ == "__main__":
				import doctest

				doctest.testmod()




