\begin{equation*}    \lim\limits_{x\rightarrow 3}{\left(\frac{x^2 + 11}{x + 1}\right)}  	= \frac{\lim\limits_{x\rightarrow 3}{(x^2 + 11)}}{\lim\limits_{x\rightarrow 3}{(x+1)}} 	= \frac{(3)^2 + 11}{3 + 1} 	= \frac{20}{4} = 5 \end{equation*}