well, in base 256 each digit is basically a byte byte is 8 bits number, so a number in base 2 using 8 digits
So if i understand it right, since a byte = 8 bit in base 2 we have 2^8 = 256 possible values. In base 256 a bit would contain 256 possible values, that is what in base 2 would be contained in an entire byte. So that's why "each byte is a digit". Do you think it's correct?