We look at the division of 59753 by 31 
We're looking to find how many times 31 goes into 59753.

Advancing to step 1:
31 can be fit into 5 0 times, resulting in a remainder of 5.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
Subtracting 0 from 5 leaves us with 5.
Fetch the next digit (9) from the dividend, attach it to 5 and continue: 59 / 31

Going ahead to step 2:
31 goes into 59 1 times with a remainder of 28.
The number 1 becomes the next digit in our result. 
Result so far: 1.0
Subtracting 31 from 59 leaves us with 28.
Append the next digit (7) from the dividend to 28 and continue with: 287 / 31

Let's proceed to step 3:
If we divide 287 by 31, we get 9 and a remainder of 8.
Put 9 as the next digit of the answer. 
Result so far: 19.0
If we take 279 away from 287, we end up with 8.
Grab the next digit (5) from the dividend, add it to 8, then carry on: 85 / 31

Moving on to step 4:
When dividing 85 by 31, we get 2 with a remainder of 23.
Use 2 as the next digit of our solution. 
Result so far: 192.0
Subtracting 62 from 85 leaves us with 23.
Fetch the next digit (3) from the dividend, attach it to 23 and continue: 233 / 31

Advancing to step 5:
31 can be fit into 233 7 times, resulting in a remainder of 16.
Record the quotient 7 as the next digit in the result. 
Result so far: 1927.0
The remainder is 16 after subtracting 217 from 233.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Moving on to step 6:
31 can be fit into 160 5 times, resulting in a remainder of 5.
Record the quotient 5 as the next digit in the result. 
Result so far: 1927.5
If we subtract 155 from 160, we get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 7:
50 divided by 31 is 1 with a remainder of 19.
Use 1 as the next digit of our solution. 
Result so far: 1927.51
Subtracting 31 from 50 leaves us with 19.
Since there are no more digits in the dividend, we add a zero to the remainder making it 190, and continue the process.

On to step 8:
190 divided by 31 is 6 with a remainder of 4.
The number 6 becomes the next digit in our result. 
Result so far: 1927.516
The remainder is 4 after subtracting 186 from 190.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 9:
31 can be fit into 40 1 times, resulting in a remainder of 9.
Use 1 as the next digit of our solution. 
Result so far: 1927.5161
The remainder is 9 after subtracting 31 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

Going ahead to step 10:
The number 31 fits into 90 2 times, leaving a remainder of 28.
Put 2 as the next digit of the answer. 
Result so far: 1927.51612
Subtract 62 from 90 to get 28.
Since there are no more digits in the dividend, we add a zero to the remainder making it 280, and continue the process.

Advancing to step 11:
The number 31 fits into 280 9 times, leaving a remainder of 1.
Record the quotient 9 as the next digit in the result. 
Result so far: 1927.516129
The remainder is 1 after subtracting 279 from 280.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Moving on to step 12:
When dividing 10 by 31, we get 0 with a remainder of 10.
Record the quotient 0 as the next digit in the result. 
Result so far: 1927.516129
If we subtract 0 from 10, we get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Going ahead to step 13:
100 divided by 31 is 3 with a remainder of 7.
Put 3 as the next digit of the answer. 
Result so far: 1927.51612903
If we subtract 93 from 100, we get 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

The final result is 1927.51612903 with a remainder of 7e-09.