972807 ÷ 19 
Let's see how many times 19 fits into 972807.

Going ahead to step 1:
19 goes into 9 0 times with a remainder of 9.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
Subtracting 0 from 9 leaves us with 9.
Grab the next digit (7) from the dividend, add it to 9, then carry on: 97 / 19

Step 2:
97 divided by 19 is 5 with a remainder of 2.
The number 5 becomes the next digit in our result. 
Result so far: 5.0
Subtract 95 from 97 to get 2.
Append the next digit (2) from the dividend to 2 and continue with: 22 / 19

On to step 3:
19 can be fit into 22 1 times, resulting in a remainder of 3.
The number 1 becomes the next digit in our result. 
Result so far: 51.0
Subtract 19 from 22 to get 3.
Include the next digit (8) from the dividend after 3, then repeat: 38 / 19

On to step 4:
If we divide 38 by 19, we get 2 and a remainder of 0.
Use 2 as the next digit of our solution. 
Result so far: 512.0
Subtracting 38 from 38 leaves us with 0.
Bring next digit (0) of the dividend behind the 0 and repeat the process: 0 / 19

Step 5:
If we divide 0 by 19, we get 0 and a remainder of 0.
Put 0 as the next digit of the answer. 
Result so far: 5120.0
If we subtract 0 from 0, we get 0.
Include the next digit (7) from the dividend after 0, then repeat: 7 / 19

Step 6:
19 goes into 7 0 times with a remainder of 7.
The next digit of our result is 0. 
Result so far: 51200.0
Deduct 0 from 7 and we're left with 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

Going ahead to step 7:
19 can be fit into 70 3 times, resulting in a remainder of 13.
The next digit of our result is 3. 
Result so far: 51200.3
If we take 57 away from 70, we end up with 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Moving on to step 8:
19 goes into 130 6 times with a remainder of 16.
Write down 6 as next digit of the result. 
Result so far: 51200.36
The remainder is 16 after subtracting 114 from 130.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Moving on to step 9:
19 can be fit into 160 8 times, resulting in a remainder of 8.
Write down 8 as next digit of the result. 
Result so far: 51200.368
Subtract 152 from 160 to get 8.
Since there are no more digits in the dividend, we add a zero to the remainder making it 80, and continue the process.

On to step 10:
When dividing 80 by 19, we get 4 with a remainder of 4.
The next digit of our result is 4. 
Result so far: 51200.3684
Deduct 76 from 80 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 11:
19 goes into 40 2 times with a remainder of 2.
Put 2 as the next digit of the answer. 
Result so far: 51200.36842
The remainder is 2 after subtracting 38 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 12:
19 can be fit into 20 1 times, resulting in a remainder of 1.
Write down 1 as next digit of the result. 
Result so far: 51200.368421
If we take 19 away from 20, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Let's proceed to step 13:
10 divided by 19 is 0 with a remainder of 10.
Record the quotient 0 as the next digit in the result. 
Result so far: 51200.368421
The remainder is 10 after subtracting 0 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

On to step 14:
100 divided by 19 is 5 with a remainder of 5.
The next digit of our result is 5. 
Result so far: 51200.36842105
Deduct 95 from 100 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

After the division, we end up with 51200.36842105 and a remainder of 5e-09.